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Thermodynamics problem -- Steam cooled until it is just dry saturated

  1. Oct 29, 2017 #1
    "HOMEWORK" PROBLEM ORIGINALLY POSTED IN WRONG FORUM, SO NO TEMPLATE

    a rigid vessel of volume 1m^3 contains steam at 25 bar and 450c the vessel is cooled until the steam is just dry saturated calculate the mass in the vessel the final pressure and the heat rejected during the process?
    i know i have to use the temperature table i tried to solve it i just want to make sure that i clearly understand .. thanks in advance
     
    Last edited by a moderator: Oct 29, 2017
  2. jcsd
  3. Oct 29, 2017 #2
    Is this a homework problem?
     
  4. Oct 29, 2017 #3
    no that's a problem my professor solved it in today's lecture but i didn't clearly understand so i tried to solve it again but my fault is that i didn't write the final answers :/
     
  5. Oct 29, 2017 #4
    This is still a homework-like problem, so I am moving it to the homework forums (Engineering and Computer Science).

    In the initial state, from your steam tables, what is the specific volume of your superheated steam?
     
  6. Oct 29, 2017 #5
    it's .13
     
  7. Oct 29, 2017 #6
    So, based on this, what is the mass of water in the vessel?
     
  8. Oct 30, 2017 #7
    i think it's V/v so it's 7.69 kg i could calculate the mass and the final pressure , i amn't sure though, but my main problem is with the heat rejected
     
  9. Oct 30, 2017 #8
    How did you determine the final pressure? What is the specific volume in the final saturated state?
     
  10. Oct 30, 2017 #9
    first of all thanks of your attention and for your time...
    the specific volume is constant right? so the pressure can be determined from the table as v(double dash) = .13?
     
  11. Oct 30, 2017 #10
    Excellent. So you know the final state. The key to getting the rejected heat is the word "rigid" in the problem statement. How much work does the steam do on the rigid vessel in this problem? From the first law, what does that tell you about the relationship between the change in internal energy and the heat?
     
  12. Oct 31, 2017 #11
    do you mean it's a closed system so i have to use the equation " delta h = delta u + delta P * v" ?? then i have to determine delta h from the table and i know the value of specific volume and of course i can determine delta p .. am i right? :/ .. thanks in advance
     
  13. Oct 31, 2017 #12
    No. I mean that $$\Delta U=Q$$
     
  14. Nov 1, 2017 #13
    yes but how can i calculate the delta U :/ ?
     
  15. Nov 1, 2017 #14
    You know everything about the initial state, so you know the internal energy for that.

    For the final state, you know that it is dry saturated, and you know its specific volume, so you should be able to precisely pinpoint this state in your steam tables. You can then determine its internal energy.
     
  16. Nov 2, 2017 #15
    oh i got your point .. Thanks alot i really appreciate your valuable time
     
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