Two part question, I can answer the first one, but i don't know how A 200g calorimeter made of aluminum contains 500g of water at 20°C. A 100g piece of ice is cooled to -20°C and is placed in the calorimeter. (a)Find the final temperature of the system, assuming no heat loss. (b)If we are to add a second 200g piece of ice at -20°C, how much ice remains in the system after it reaches equilibrium? Some Constants and Equations Specific Heat of Ice=2.0kJ/kg°C Specific Heat of Water=4.186kJ/kg°C Specific Heat of Aluminum=.91kJ/kg°C Q=mcΔT and Q=mL I answered the first one(a) and got 16.77°C. I tried to answer the second one(b) Q(1)=mcΔT=(.2kg)(2.0kJ/kg°C)(0°C-(-20°C)) [From -20°C to 0°C] Q(2)=mL=(.2kg)(334kJ/kg)=66.8kJ [Ice-To-Water] I'm stuck here... Also, am I doing it right? Thanks for any help.