Thermodynamics question. Could be simpler than it looks, but I am really stuck.

Jasbraman
Messages
3
Reaction score
0
Precisely what does the following equation, in which R is the gas constant, allow one to calculate?



ln xs = -dHf/R(T0-T/TT0)



I have no idea what this could be. I know what each part of the equation is (gas constant, change in enthalpy of formation, Freezing point depression etc.) I just don't know what it allows me to calculate...except that its the natural log of something. I think it has something to do with entropy, but I'm not sure. Any help would be much appreciated.
 
Last edited:
Physics news on Phys.org
Notation is ambiguous. Did you mean

<br /> \ln x_s = \frac{-dH_f}{R}\left(\frac{T_0-T}{TT_0}\right)<br />

in which case x_s is dimensionless?
 
That is exactly what I meant, yes. I did not know you could put in equations like that. Anyway, I have to find out precisely what it allows me to calculate, but I have no idea.
 
Jasbraman said:
That is exactly what I meant, yes. I did not know you could put in equations like that. Anyway, I have to find out precisely what it allows me to calculate, but I have no idea.

Try this:
1. the expression with T can be rewritten as two terms
2. exponentiate
 
Last edited:
That should give you something that looks a lot like something else you're familiar with :-/
 
Oohhhhh yeeeah! Thanks for that!
 
To solve this, I first used the units to work out that a= m* a/m, i.e. t=z/λ. This would allow you to determine the time duration within an interval section by section and then add this to the previous ones to obtain the age of the respective layer. However, this would require a constant thickness per year for each interval. However, since this is most likely not the case, my next consideration was that the age must be the integral of a 1/λ(z) function, which I cannot model.
Back
Top