Thermodynamics question. Could be simpler than it looks, but I am really stuck.

AI Thread Summary
The equation ln xs = -dHf/R(T0-T/TT0) relates to thermodynamic calculations involving the change in enthalpy of formation and can be used to derive properties such as freezing point depression. The discussion highlights confusion regarding the equation's implications, specifically what it allows one to calculate. Clarification was provided that the notation can be rewritten and exponentiated to reveal familiar relationships in thermodynamics. The dimensionless nature of xs is emphasized, indicating its significance in the context of the equation. Overall, understanding this equation can enhance insights into thermodynamic behavior and calculations.
Jasbraman
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Precisely what does the following equation, in which R is the gas constant, allow one to calculate?



ln xs = -dHf/R(T0-T/TT0)



I have no idea what this could be. I know what each part of the equation is (gas constant, change in enthalpy of formation, Freezing point depression etc.) I just don't know what it allows me to calculate...except that its the natural log of something. I think it has something to do with entropy, but I'm not sure. Any help would be much appreciated.
 
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Notation is ambiguous. Did you mean

<br /> \ln x_s = \frac{-dH_f}{R}\left(\frac{T_0-T}{TT_0}\right)<br />

in which case x_s is dimensionless?
 
That is exactly what I meant, yes. I did not know you could put in equations like that. Anyway, I have to find out precisely what it allows me to calculate, but I have no idea.
 
Jasbraman said:
That is exactly what I meant, yes. I did not know you could put in equations like that. Anyway, I have to find out precisely what it allows me to calculate, but I have no idea.

Try this:
1. the expression with T can be rewritten as two terms
2. exponentiate
 
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That should give you something that looks a lot like something else you're familiar with :-/
 
Oohhhhh yeeeah! Thanks for that!
 
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