Thevenin equivalent of lattice network

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The discussion focuses on finding the Thevenin equivalent of a lattice network viewed from terminals As and Br. Participants suggest using voltage dividers to determine node voltages and consider the impact of resistor f on impedance. The Y-Δ transformation is recommended as a method to simplify the network analysis, particularly with the presence of triangles in parallel. Additionally, it's noted that resistor e is directly between the output nodes, making it effectively parallel with other components. The conversation emphasizes the importance of redrawing the circuit for better insights and problem-solving.
Mbert
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Homework Statement


Find the Thevenin equivalent network of the lattice network (see attached), viewed from points As and Br (terminals Bs and Ar are not connected to anything).


Homework Equations





The Attempt at a Solution


Without the resistance f, the problem is quite simple. I can find voltages at nodes Bs and Ar as a function of voltage between As and Br (potential dividers). Then insert f and check how it modifies the impedance? I think it only works to check the Thevenin impedance between Bs and Ar, not As and Br, but I'm not sure. Any help would be appreciated.
 

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Sometimes redrawing the diagram can provide insight. Relocate the node Bs to the interior of triangle AsArBr and see what you get.
 
I'm guessing I have to use the Y-D transformation, so I get 2 triangles in parallel?
 
Mbert said:
I'm guessing I have to use the Y-D transformation, so I get 2 triangles in parallel?

There are several ways to continue, one of which is certainly to employ a Y-Δ transform.

You might want to note that resistor e runs directly between the "output" nodes, so it is in effect in parallel with all the rest. You could always remove it for now, figure out the resistance of the rest, then put e back in parallel to finish up.
 
Yes, many thanks.
 

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