Thevenin Equivalent with a dependent source

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To find the Thevenin Equivalent circuit between points A and B, all resistances in that section should be combined into a single equivalent resistor, while voltage sources are reduced to one source. The presence of a dependent source requires calculating the voltage across it, which can be expressed in terms of another voltage (vx). Using techniques like Kirchhoff's Current Law (KCL) and Kirchhoff's Voltage Law (KVL) or node analysis can help determine the value of vx. Understanding these concepts is crucial for successfully simplifying the circuit. The discussion emphasizes that encountering a dependent source should not be intimidating.
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Find the Thevenin Equivalent circuit between A and B
the circuit is in the attachments...

i don't know how to start and don't know what it meas "Between A and B"
and i never encountered a problem with a dependent source.

Thanks...
 

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Thevenin circuit is a resistor and voltage source in series.

To reduce the circuit to a thevenin equivalent circuit you would replace all the resistances between a and b with one equivalent resistor and reduce the voltage sources to one source.

think of two parallel resistors being represented as one resistor it's similar to this except you have a bunch of resistors and a dependent source as well.

as for the dependent source you shouldn't panic. if you can find the voltage vx then you know the voltage across the dependent source is just 5vx.
 
anthonuc said:
Thevenin circuit is a resistor and voltage source in series.

To reduce the circuit to a thevenin equivalent circuit you would replace all the resistances between a and b with one equivalent resistor and reduce the voltage sources to one source.

think of two parallel resistors being represented as one resistor it's similar to this except you have a bunch of resistors and a dependent source as well.

as for the dependent source you shouldn't panic. if you can find the voltage vx then you know the voltage across the dependent source is just 5vx.
right, but how can i find Vx?
 
hopefully you know how to use kcl and kvl if not node analysis.
 
thanks
 
Last edited:
no problem.
 

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