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Thevenin Equivalent with a dependent source

  • Thread starter RedDead
  • Start date
  • #1
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Find the Thevenin Equivalent circuit between A and B
the circuit is in the attachments...

i don't know how to start and don't know what it meas "Between A and B"
and i never encountered a problem with a dependent source.

Thanks...
 

Attachments

Answers and Replies

  • #2
12
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Thevenin circuit is a resistor and voltage source in series.

To reduce the circuit to a thevenin equivalent circuit you would replace all the resistances between a and b with one equivalent resistor and reduce the voltage sources to one source.

think of two parallel resistors being represented as one resistor it's similar to this except you have a bunch of resistors and a dependent source as well.

as for the dependent source you shouldn't panic. if you can find the voltage vx then you know the voltage across the dependent source is just 5vx.
 
  • #3
8
0
Thevenin circuit is a resistor and voltage source in series.

To reduce the circuit to a thevenin equivalent circuit you would replace all the resistances between a and b with one equivalent resistor and reduce the voltage sources to one source.

think of two parallel resistors being represented as one resistor it's similar to this except you have a bunch of resistors and a dependent source as well.

as for the dependent source you shouldn't panic. if you can find the voltage vx then you know the voltage across the dependent source is just 5vx.
right, but how can i find Vx?
 
  • #4
12
0
hopefully you know how to use kcl and kvl if not node analysis.
 
  • #5
8
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thanks
 
Last edited:
  • #6
12
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no problem.
 

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