Thevenin Equivalent with a dependent source

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Discussion Overview

The discussion revolves around finding the Thevenin Equivalent circuit between two points, A and B, in a circuit that includes a dependent source. Participants explore the concept of Thevenin equivalents and express uncertainty regarding the process, particularly in relation to dependent sources.

Discussion Character

  • Exploratory
  • Technical explanation
  • Homework-related

Main Points Raised

  • One participant seeks clarification on how to find the Thevenin Equivalent circuit and expresses confusion about the term "Between A and B" and the presence of a dependent source.
  • Another participant explains that a Thevenin circuit consists of a resistor and a voltage source in series, suggesting that the circuit can be reduced by replacing resistances between A and B with an equivalent resistor and consolidating voltage sources.
  • A participant emphasizes that finding the voltage Vx is crucial for determining the voltage across the dependent source, which is expressed as 5Vx.
  • One participant mentions the use of Kirchhoff's Current Law (KCL) and Kirchhoff's Voltage Law (KVL) or node analysis as methods to find Vx.

Areas of Agreement / Disagreement

Participants express varying levels of understanding regarding the process of finding the Thevenin Equivalent, with some providing explanations while others seek further clarification. The discussion does not reach a consensus on the method for finding Vx or the overall approach to the problem.

Contextual Notes

Participants do not provide specific details about the circuit in question, which may limit the ability to apply the discussed methods effectively. There is also a lack of consensus on the best approach to handle the dependent source.

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Find the Thevenin Equivalent circuit between A and B
the circuit is in the attachments...

i don't know how to start and don't know what it meas "Between A and B"
and i never encountered a problem with a dependent source.

Thanks...
 

Attachments

  • IMAG0012.jpg
    IMAG0012.jpg
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Thevenin circuit is a resistor and voltage source in series.

To reduce the circuit to a thevenin equivalent circuit you would replace all the resistances between a and b with one equivalent resistor and reduce the voltage sources to one source.

think of two parallel resistors being represented as one resistor it's similar to this except you have a bunch of resistors and a dependent source as well.

as for the dependent source you shouldn't panic. if you can find the voltage vx then you know the voltage across the dependent source is just 5vx.
 
anthonuc said:
Thevenin circuit is a resistor and voltage source in series.

To reduce the circuit to a thevenin equivalent circuit you would replace all the resistances between a and b with one equivalent resistor and reduce the voltage sources to one source.

think of two parallel resistors being represented as one resistor it's similar to this except you have a bunch of resistors and a dependent source as well.

as for the dependent source you shouldn't panic. if you can find the voltage vx then you know the voltage across the dependent source is just 5vx.
right, but how can i find Vx?
 
hopefully you know how to use kcl and kvl if not node analysis.
 
thanks
 
Last edited:
no problem.
 

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