Is Finding Thévenin's Equivalent Just Calculating Rth and Vth?

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Finding Thévenin's equivalent involves calculating both the equivalent resistance (Rth) and the open-circuit voltage (Vth) of the circuit. Internal resistance of the battery must be considered in these calculations. The discussion highlights that while Rth can be determined correctly, there may be errors in calculating Vth, particularly in understanding voltage dividers. Participants emphasize the importance of double-checking calculations to avoid simple mistakes. Overall, accurately determining Rth and Vth is essential for finding Thévenin's equivalent.
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Homework Statement



Find the Thévenin's equivalent.
SF1s5J7.png


Homework Equations



V=IR

The Attempt at a Solution


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I'm not sure if I need to take into account the internal resistance. And also, is finding thévenin's equivalent just calculating Rth and Vth?

I'm really lost sorry.
Many thanks.
 
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Crutchlow13 said:
I'm not sure if I need to take into account the internal resistance. And also, is finding thévenin's equivalent just calculating Rth and Vth?
Yup, the internal resistance of the battery counts. Rth and Vth are what you're after.
 
Thanks, do you think I got it?
 

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Crutchlow13 said:
Thanks, do you think I got it?
Your Rth looks good, but something went wrong with your final calculation of Vth. If you look at the resistors in the voltage divider you'd expect to see Vth = 1/2 of your v1...
 
Oh my god that was super silly.. Thanks gneill!
 
Thread 'Variable mass system : water sprayed into a moving container'

Thread 'Variable mass system : water sprayed into a moving container'

Starting with the mass considerations #m(t)# is mass of water #M_{c}# mass of container and #M(t)# mass of total system $$M(t) = M_{C} + m(t)$$ $$\Rightarrow \frac{dM(t)}{dt} = \frac{dm(t)}{dt}$$ $$P_i = Mv + u \, dm$$ $$P_f = (M + dm)(v + dv)$$ $$\Delta P = M \, dv + (v - u) \, dm$$ $$F = \frac{dP}{dt} = M \frac{dv}{dt} + (v - u) \frac{dm}{dt}$$ $$F = u \frac{dm}{dt} = \rho A u^2$$ from conservation of momentum , the cannon recoils with the same force which it applies. $$\quad \frac{dm}{dt}...
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