Thick spherical shell confirmation of solution

AI Thread Summary
The discussion focuses on calculating the charge density ρ and the electric field for a thick spherical shell with inner radius a and outer radius b. The charge density is derived as ρ = 3Q/(4π(b³ - a³)), using the volume of the shell. The electric field is determined to be zero for r < a, E = (4πkρ(b³ - a³))/(3r³) for a < r < b, and E = kQ/r² for r > b, treating the shell as a point charge. Errors in the initial equations were identified, particularly regarding the dependence on r and the correct application of Gauss' law. The final understanding emphasizes the importance of charge enclosed within the Gaussian surface in determining the electric field.
Liquidxlax
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Homework Statement


A spherical shell of inner radius a and outer radius b contains a uniform charge density ρ of total charge Q. (a) Find ρ (b) find the electric field for r< a, a< r< b, b< r sketch it


Homework Equations



E = kQ/r2

V=4πr3

The Attempt at a Solution



ρ π

since it is a thick shell the volume would be V = (4/3)π(b3 - a3)

and ρV = Qenc => ρ=Q/V

so

ρ = 3Q/(4π(b3 - a3))


(b) r<a the electric field will be 0 because the electric field can't close on itself

a< r< b

E=kQenc/r2 = (4πkρ(b3 - a3))/3r3


b<r kQ/r2 because the sphere can be treated as a point charge and the electric field is symmetric on a sphere


Does this look right?
 
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Liquidxlax said:
E= [...] = (4πkρ(b3 - a3))/3r3
There's two errors with the above equation (see the red).
 
collinsmark said:
There's two errors with the above equation (see the red).

okay i see how the r3 is wrong, that was just a transcribing error, but how come the b is wrong? or would it be because we know that r<b so we can assume it to be

(r3-a3) because a is constant and r does not exceed b
 
There you go! :approve: Remember Gauss' law relates to the charge enclosed within the Gaussian surface (the Gaussian surface in this case has radius r). In the case where b > r > a, then any charge between r and b is outside the Gaussian surface, and has no effect (in this spherically symmetrical case).
 
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