1. The problem statement, all variables and given/known data 3. A converging lens has a focal length of 10 cm. A screen is placed 30 cm from an object. Where should the lens be placed, in relation to the object, to produce a focused image? 2. Relevant equations 1/do + 1/di = 1f 3. The attempt at a solution Do can not be greater than 2F, because then the image appears between F and 2F on the other side of the lens. From 2F to 2F is 40cm, the distance we want is 30cm. Do cannot be equal to 2F because then the image appears at 2F on the other side. 2F to 2F in this case is 40cm. So its not possible. Do cannot be between f (10cm) and 2f or the image will appear beyond 2f. F to 2F is 30cm, so the object cant be beyond F and the image cant be beyond 2F when there’s only 30cm between them. Do cannot be F because no image is formed when do is at F. Therefore, do must be less than F. However, this is not possible because the lens must be between the screen and the object, as specified by the question, and do being less than f results in the image appearing on the same side of the lens as the object. If I actually attempt it mathematically it turns into a sadistic guessing game. di + do = 30 1/do + 1/di = 1/10 How many combinations of 2 numbers sum 30? Am I expected to draw a ray diagram for all of them until I find a combo that works, or is there a formulaic way of approaching this that's going over my head? The problem being... do and di are defined in relation to the position of the lens. In this case, the position of the lens is the variable.