This is the correct average velocity for the entire trip.

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The discussion centers on calculating average velocity for a bicycle trip involving two legs: 24 km north in 2.5 hours and returning home in 1.5 hours. For the homeward leg, the average velocity is correctly calculated as 16 km/h. However, the average velocity for the entire trip is miscalculated initially; the correct formula for average velocity is the total distance divided by total time, yielding 12 km/h. Participants emphasize the importance of using the correct definitions and formulas for accurate calculations. The final consensus confirms that the average velocity for the entire trip is 12 km/h.
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1.Starting from home, you bicycle 24km north in 2.5 h and then turn around and pedal straight home in 1.5h. c)What's the average velocity for the homeward leg of the trip? e)What's the average velocity for the trip?

Equations V=x/t & avg. V=(V+V initial)(1/2)
 
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You must make some attempt at the problem to get help on Physics Forums:

https://www.physicsforums.com/showthread.php?t=94379

Where are you getting stuck? What are your thoughts on the problem? What concepts/formulas do you think apply, etc?
 
c) 24km/1.5h=16km/h
e)((24km/2.5)+16km/h)/2=12.8km/h
 
Part c is correct.

For part e) you are incorrectly using the formula you listed. You are off by a few decimal places. Start from the definition of average velocity:

v_{avg}=\frac{d_{total}}{t_{total}}=\frac{48km}{4h}=12km/h
 
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