- #1

You are using an out of date browser. It may not display this or other websites correctly.

You should upgrade or use an alternative browser.

You should upgrade or use an alternative browser.

- Thread starter unscientific
- Start date

- #1

- #2

Sourabh N

- 631

- 0

[itex](\sqrt{R^2 - x^2})[/itex] should be [itex](\sqrt{R^2 - x^2})^n[/itex]

- #3

unscientific

- 1,734

- 13

[itex](\sqrt{R^2 - x^2})[/itex] should be [itex](\sqrt{R^2 - x^2})^n[/itex]

hmm are u sure about that?

- #4

Sourabh N

- 631

- 0

Yes.

- #5

Bacle2

Science Advisor

- 1,089

- 10

- #6

Ray Vickson

Science Advisor

Homework Helper

Dearly Missed

- 10,706

- 1,722

## Homework Statement

The question is attached in the picture.

## The Attempt at a Solution

Since V_{0}= 1,

Thus V_{1}= [itex]\stackrel{1}{2}[/itex]∏R^{2}which is a constant.

Then shouldn't V_{n}be as in the picture?

[tex] V_1(R) =

\int_{-R}^R V_0 \left(\sqrt{R^2-x^2} \right) \, dx = \int_{-R}^R \; 1 \, dx = 2R, [/tex]

etc.

RGV

Share:

- Replies
- 13

- Views
- 419

- Replies
- 9

- Views
- 575

- Replies
- 34

- Views
- 816

- Last Post

- Replies
- 1

- Views
- 328

- Replies
- 6

- Views
- 323

- Replies
- 5

- Views
- 385

- Replies
- 5

- Views
- 730

- Replies
- 1

- Views
- 325

- Replies
- 8

- Views
- 670

- Last Post

- Replies
- 3

- Views
- 304