This should be an easy one: Work required to change speed

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SUMMARY

The discussion centers on calculating the work required to double the speed of an object with kinetic energy (K). According to the work-kinetic energy theorem, the work done on an object equals the change in its kinetic energy. To determine the work needed, one must understand the relationship between kinetic energy and speed, specifically that kinetic energy is proportional to the square of the speed. Therefore, doubling the speed results in a fourfold increase in kinetic energy, necessitating work equal to the difference in kinetic energy.

PREREQUISITES
  • Understanding of the work-kinetic energy theorem
  • Knowledge of kinetic energy formula: K = 0.5 * m * v²
  • Basic algebra for manipulating equations
  • Familiarity with concepts of speed and energy in physics
NEXT STEPS
  • Study the derivation of the kinetic energy formula
  • Learn about the implications of the work-energy theorem in different contexts
  • Explore examples of work done in various physical scenarios
  • Investigate the relationship between speed, mass, and kinetic energy in real-world applications
USEFUL FOR

This discussion is beneficial for physics students, educators, and anyone interested in understanding the principles of kinetic energy and work in mechanics.

atrain77a
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Hi, I apologize for the simplicity here, I'm just getting started. Here's the question:

An object has kinetic energy, K. How much work do you have to do to double the speed of the object?

Any suggestion on how to start this would be much appreciated. :smile:
 
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The work-kinetic energy theorem states that the work done on a particle equals the change in kinetic energy of the particle. From that statement, you should have enough information to answer your question.
 
In order to use TALewis' hint, you will need to know how kinetic energy depends on speed.
 

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