Throwing a Short Put - simple Distance problem?

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The discussion revolves around a physics problem involving projectile motion, specifically the distance a shotput travels when thrown at different angles. The initial throw at a 45-degree angle covers 30 meters, and the user seeks to determine the new range when the angle is increased to 55 degrees. There is confusion regarding the application of the distance formula and the correct use of velocity components. The user requests clarification on the concepts and equations related to projectile motion rather than a direct solution. Understanding the trajectory and range calculations is crucial for solving the problem effectively.
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Homework Statement


Boy throws a shotput at angle of 45Degree which travels a horizontal distance of 30m
If he releases same shotput at same speed but changes angle to 55 Degree, what will be the new range or distance?
A) 25m B)41m C)28m D)37m E)32. m

Homework Equations


That's what i am finding.?/?


The Attempt at a Solution



I tried using the info posted somewhere like
Distance = 1/2 * (acceleration) * (time squared) + (Velocity) * (Initial time) + (Initial Distance)
But i am not able to get what to put where? what to put in velocity? horizontal or vertical?
I am not even sure this is correct way.
Pleas hlp...driving me nuts!
Just explain me the concept with equation, if you do not want to solve for me. please
 
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Thanks for your help. That worked nicely :biggrin:
 

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