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How do you properly solve for the time till an object hits the ground when its thrown upwards off a cliff? With only The initial velocity and the hieght of the cliff. Thx 
The initial velocity of an object thrown upwards from a cliff can vary depending on the strength and angle of the throw, as well as other factors such as air resistance. However, it is generally calculated to be zero since the object starts at rest before being thrown.
The height of the cliff will affect the time it takes for the object to reach the ground. The higher the cliff, the longer it will take for the object to fall due to the force of gravity. This can be calculated using the equation t = √(2h/g), where t is time, h is height, and g is the acceleration due to gravity.
Air resistance can have a significant impact on an object thrown upwards from a cliff. As the object moves through the air, it will experience resistance which will slow it down. This can result in a shorter distance traveled and a longer time in the air compared to a scenario without air resistance.
The maximum height an object can reach when thrown upwards from a cliff is dependent on its initial velocity and the height of the cliff. In theory, the maximum height would be infinite, but in reality, air resistance and other factors will limit the height the object can reach.
Yes, an object thrown upwards from a cliff can have a negative velocity, particularly as it reaches its maximum height and begins to fall back towards the ground. Negative velocity simply means the object is moving downward, and it is a natural part of the object's trajectory when thrown upwards from a cliff.