Thrust of an underpressure tank of air

AI Thread Summary
To calculate the thrust of an underpressure tank of air when the valve is released, one must consider the mass flow rate and velocity of the escaping air, which can be approximated using Bernoulli's principle. The discussion clarifies that "underpressure" refers to the thrust produced by air escaping from a compressed air cylinder, not a pressure less than ambient. A formula involving the pressure in the tank and the area of the orifice is suggested, but it is noted that thrust calculations depend on additional variables beyond just these factors. The conversation highlights the importance of precise terminology and understanding the physics behind thrust generation. Accurate measurements or experiments may be necessary for precise calculations.
Raresss
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How can I calculate the thrust of an underpressure tank of air when the valve is released? If you can, please, explain in detail. Thank you!
 
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"Underpressure?" Less than ambient?
 
Bystander said:
"Underpressure?" Less than ambient?
More than the ambient pressure
 
Raresss said:
More than the ambient pressure
Pressure "under" what? Do you mean when it's running out?
 
The OP just means the thrust produced by air escaping from a cylinder of compressed air.

Most people in my country understand "under" to mean "due to". As in "The bridge failed under the weight of traffic".
 
CWatters said:
The OP just means the thrust produced by air escaping from a cylinder of compressed air.

Most people in my country understand "under" to mean "due to". As in "The bridge failed under the weight of traffic".
I can see that now. In English, underpressure and "underweight" (compound words) have different meanings from when the two words are separated by a space; hence my confusion. If this were a German forum, things might be different. . . :smile:
 
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Can the mass flow rate and the velocity of the exhausted gas be calculated or those can only be measured in an experiment ?
 
Raresss said:
Can the mass flow rate and the velocity of the exhausted gas be calculated or those can only be measured in an experiment ?

Bernoulli should be a good approximation.

sophiecentaur said:
If this were a German forum, things might be different. . . :smile:

Not really. "Unterdruck" instead of "unter Druck" would result in the same confusion.
 
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Would it not just be the pressure in the tank x the area of the orifice?
I.E. If the pressure is 1 Mpa (above ambient) and the orifice is 12mm then the thrust should be 1 Newton, right?
 
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mrspeedybob said:
Would it not just be the pressure in the tank x the area of the orifice?
I.E. If the pressure is 1 Mpa (above ambient) and the orifice is 12mm then the thrust should be 1 Newton, right?
Your force is the normal force, and your pressure is the surface pressure. We can't use those in my problem. The thrust is based on other variables . Check out this link to find out more : https://en.wikipedia.org/wiki/Thrust
 

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