Time for boat to make two sets of displacements

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The discussion revolves around calculating the time it takes for a boat to make a round trip downstream and upstream in a river. The boat travels at 6.1 m/s relative to the water, with the river current flowing at 2.4 m/s. The user initially calculated the resultant speed using the Pythagorean theorem but later realized that the downstream speed should be 8.5 m/s and the upstream speed 3.7 m/s. They expressed confusion about how to correctly apply the distance equals velocity times time formula for both segments of the trip. The conversation emphasizes understanding relative motion and how to accurately compute travel times in varying conditions.
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Homework Statement



I would really appreciate if someone could check my work for this poblem b.c i seem to be getting the wrong answer.

Problem: A boat moves through a river at 6.1 m/s relative to the water, regardless of the boat's direction. If the water in the river is flowing at 2.4 m/s, how long does it take the boat to make a round trip consisting of a 246 m displacement downstream followed by a 194 m displacement upstream? Answer in units of seconds.

First, I used the pythagorean theorem to find the resultant vector- 6.555150647m/s. Then, used distance=Velocity * time . I plugged in 246m for distance and 2.4m/s for the velocity to get 102.5 sec for time. I did the same thing with the second displacement to get 183.3333333s for time. Then I added them together for a total time of 183.3333333s.
 
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If its going down stream then up stream surly that means its going from A to B and then B to A.
If its moving 6.1m/s relative to the water down stream it would be moving at 8.5m/s
up stream it would be moving at 3.7m/s (unless it is taking 6.1m/s as its actual velocity, but then why would you have the speed of the water?).
 
hmm i kinda follow, but how do you find the time?
 
With distance = velocity * time. If your having trouble with the boat moving relative to the water think of trying to measure the speed of a car from inside another moving car. If you were measuring car A (30mph) from car B (20mph) it would look like car A is going 10mph.
 
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