Time for Revolution (Rotating about the Center of Mass)

AI Thread Summary
The discussion revolves around a physics problem involving two men rotating on a frictionless surface while connected by a rope. The key focus is on the conservation of angular momentum and the calculation of angular inertia as the distance between them changes from 15 m to 10 m. The user initially struggles with the arithmetic and unit conversions, particularly in relating angular velocity to the time taken for one complete revolution. Clarifications are provided regarding the use of symbolic calculations instead of numerical ones to avoid confusion. Ultimately, it is suggested that the book's provided answer may be incorrect.
Redfire66
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Homework Statement


Two men with masses 70 kg and 120 kg rotate at 1 rpm on a frictionless surface and are attached by a 15 m rope.
If they pull the rope so that only 10 m is between them when they rotate, how long does it take to make 1 revolution?

Homework Equations


Angular Momentum and Inertia

The Attempt at a Solution


So I found the center of masses for when the distances are 15 m apart and 10 m apart. I assume that angular momentum is conserved since there's nothing that really seems to affect it when I read it.
So L = L
Then Inertia = sum mr^2
Hence (m1r1^2 + m2r2^2)w1 = (m1r3^2 + m2r4^2)w2 where r1, r2, are distances from the center of mass for the 15 m, and r3 and r4 are the distances from the center of mass for the 10 m distance.
I1w1 = I2w2; I'm kind of confused by most of the radian conversions and such.
For what I got I1 = 9947.4kgm^2 and I2 = 4420.8kgm^2
Putting this together I got 9947(2pi rad/60s) = 4421(w2) then w2 = 2 .3rad/s. I assume I did something wrong, also I can't figure how I would convert it to 1 revolution, would I divide it by 2pi*r?
I did try it however it should be 40 seconds given as the answer in my book which I did not get
 
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Redfire66 said:
9947(2pi rad/60s) = 4421(w2) then w2 = 2 .3rad/s
Check your arithmetic.
Redfire66 said:
1 revolution, would I divide it by 2pi*r?
2π radians is one full circle. Multiplying by r gives you the length of the arc, or circumference.
 
Bystander said:
Check your arithmetic.

2π radians is one full circle. Multiplying by r gives you the length of the arc, or circumference.
Okay thanks I'll look into it.
Edit: yeah I actually meant 2pir/w instead. Mistyped
 
Redfire66 said:
I meant 2rpi/w. However that doesn't yield anything
It yields m/s, which you are not interested in for this problem. Pay attention to units.
Redfire66 said:
What do you mean by checking my arithmetic?
When I suggest that you check your arithmetic, it means you've made an error, and you should go through your work and find it.
 
It is always better, for a raft of reasons, to work entirely symbolically, only plugging in numbers as the final step.
In this case, it would have avoided the conversion to rad/s and back, which seems to have confused you. You could have worked with rpm throughout instead, but keeping it symbolic you don't care about units until the numbers are plugged in.
By the way, the book answer is wrong, as I expect you will discover.
 
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