Time it takes for a RC circuit to fully charge

AI Thread Summary
An RC circuit takes an indefinite time to fully charge, as the current decreases towards zero as the capacitor voltage approaches the supply voltage. The charging equation Q=CV(1-e^(-t/RC) indicates that the capacitor will never reach a fully charged state in a finite time. However, after approximately five time constants (5 * RC), the voltage across the capacitor is within 1% of the supply voltage, which is often considered effectively charged. The confusion arises from the initial condition of the capacitor being uncharged, leading to difficulties in applying the natural logarithm in calculations. Understanding the behavior of current and voltage in the circuit is crucial for solving these types of problems.
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Homework Statement


How much time does an RC circuit require to become fully charged assuming that the capacitor was initially uncharged.
resistance = R
capacitance = C
Voltage = V

Homework Equations


Q=CV(1-e^(-t/RC)

The Attempt at a Solution


so T = -ln(Q/(CV) - 1)RC
but Q = 0 since it's initially uncharged?
so T=-ln(0-1)RC

I'm not quite sure what to do for this problem because this error isn't in the domain of the natural log. Honestly, I don't even understand the formula, if CV is the final possible charge, then is Q=CV?
 
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Consider the current through the resistor...

I = VR/R

where the voltage VR across the resistor = Source Voltage - Capacitor voltage

So as the capacitor voltage rises the current through the resistor falls. This reduces the rate at which the capacitor charges. In theory the capacitor never becomes fully charged because the current falls towards zero.

The voltage on the capacitor looks like this..

http://www.interfacebus.com/RC-Time-Constant-Rising-Voltage-Chart.jpg

After "5 time constants" (eg 5 * RC) the voltage will be within 1% of the supply voltage.
 
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