Time period formula-proof required

[IB1]

Hello everyone, I'm new here, sorry if I make mistakes. My english is poor.

Prove that :
T=2\pi \sqrt{\frac{l}{g}}
where l is length and g is gravity

I hope you understand my question, else: I will try to write it again.
Thank you !

 

[tiny-tim]

Welcome to PF!

Hi IB1! Welcome to PF!

Show us what you've tried, and where you're stuck, and then we'll know how to help!

 

[IB1]

Thank you tiny-tim, It's nice joining this forum.

As for the problem: Well, I don't know even how to start proving this. I was first thinking for any trigonometric solution but I can not understand how the period can be independent from the angle. Hope you understand to which angle I refer.

It is not necessary to give an own proof, a link would be good enough.

 

[tiny-tim]

Hi IB1!

(just got up :zzz: …)

It's difficult to know how to help without knowing how advanced your knowledge is …

which part of the course is this in (for example, have you done calculus)?

Maybe this will help … http://en.wikipedia.org/wiki/Pendulum"

 

[IB1]

Thank you, the link was useful. You understood what I was asking :) . As for Calculus, yes -I know Calculus.

It Seems that I was right, the period is not very independent from the angle \theta .