Time taken to reach the water's surface

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SUMMARY

The discussion focuses on calculating the time taken for a thin spherical shell filled with helium to reach the surface of water from a depth of 3.77 meters. The shell has a mass of 3.30 kg and a diameter of 0.225 m, with an acceleration of 7.91 m/s² determined through the application of buoyancy principles. The user attempts to solve for time using the equation Δd = Vi*t + 0.5at² but encounters issues with a negative value under the square root, indicating a misunderstanding of the displacement sign convention. The correct approach requires ensuring that the displacement (Δd) is treated consistently with the defined coordinate system.

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Homework Statement



A thin spherical shell with a mass of 3.30 kg and a diameter of 0.225 m is filled with helium (density = 0.180 kg/m3). It is then released from rest on the bottom of a pool of water that is 3.77 m deep. Neglecting frictional effects, determine the value of that acceleration.
Correct, computer gets: 7.91E+00 m/s^2

How long does it take for the top of the shell to reach the water's surface?

Homework Equations





The Attempt at a Solution



so i know that to reach the top of the container it would travel 3.77 m and that vinitial = 0m/s and we know that acceleration is 7.91m/s^2 so i used the equation

[tex]\Delta[/tex]d= Vi*t+0.5at2
-3.77m=0+0.5(7.91)t2
and when i solve this i get a negative under the root which i know isn't right..pls help
 
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In doing this problem, you've implicitly defined the "up" direction as being positive. So why is your delta d negative?
 
even if i put my delta d as positive i still get the wrong answer
 

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