Too fast for a black hole to consume?

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The discussion centers around the implications of a pulsar moving at 6 million miles per hour colliding with a black hole. It raises questions about whether a fast-moving pulsar could bypass a black hole due to its speed and size, and how black holes interact with incoming matter. It clarifies that once any part of an object crosses a black hole's event horizon, it is irretrievably lost, while parts outside may be ejected or enter orbit. The conversation also touches on frame dragging effects during such collisions and references equations that describe the behavior of objects falling into black holes. Ultimately, the event horizon serves as a boundary beyond which escape is impossible, regardless of the object's speed.
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I read an article yesterday about the fastest moving pulsar yet detected. The Chandra X-ray observatory spied a pulsar in SNR MSH 11-61A and IGR J11014-6103 moving at approximately 6 million miles an hour. This raised the question in my mind of what would happen if this pulsar were to collide with a stellar sized black hole moving at such rate with respect to the black hole. Does a black hole have a "processing" rate where it converts hadrons into whatever the form of matter or energy is inside a black hole? Is the conversion instantaneous? Is it possible for a fast moving pulsar to blow right through a black hole because it is too big and moving too fast to eat? Or how about two black holes moving toward each other with a combined speed approaching the speed of light? Would the black holes collide like billiard balls? I hope these questions are not too naive but I am merely an arm-chair astro-physicist wannabe.
 
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Once something has crossed the event horizon there is no getting out, even at the speed of light. Note that a black hole does not "eat" or "process" anything. The event horizon of the black hole is not a physical surface, it is simply a boundary that marks the point where the escape velocity exceeds the speed of light.

So if a pulsar was to collide with a black hole any part of it that is smaller than the event horizon is lost for good, the parts that are outside will either fly off very fast as they slingshot round the BH or fall in or go into orbits (perhaps falling in later).
 
Ryan_m_b said:
Once something has crossed the event horizon there is no getting out, even at the speed of light. Note that a black hole does not "eat" or "process" anything. The event horizon of the black hole is not a physical surface, it is simply a boundary that marks the point where the escape velocity exceeds the speed of light.

So if a pulsar was to collide with a black hole any part of it that is smaller than the event horizon is lost for good, the parts that are outside will either fly off very fast as they slingshot round the BH or fall in or go into orbits (perhaps falling in later).

The frame dragging would also have an effect depending upon the angle and direction of collision.
 
Boliver said:
I read an article yesterday about the fastest moving pulsar yet detected. The Chandra X-ray observatory spied a pulsar in SNR MSH 11-61A and IGR J11014-6103 moving at approximately 6 million miles an hour. This raised the question in my mind of what would happen if this pulsar were to collide with a stellar sized black hole moving at such rate with respect to the black hole. Does a black hole have a "processing" rate where it converts hadrons into whatever the form of matter or energy is inside a black hole? Is the conversion instantaneous? Is it possible for a fast moving pulsar to blow right through a black hole because it is too big and moving too fast to eat? Or how about two black holes moving toward each other with a combined speed approaching the speed of light? Would the black holes collide like billiard balls? I hope these questions are not too naive but I am merely an arm-chair astro-physicist wannabe.

According to 'Exploring Black Holes' by Wheeler & Taylor, there are three types of in-falling radial plunger for a static black hole-

Drip (dropped from rest at r_o)

Rain (dropped from rest at infinity)

Hail (hurled inward at speed v_{far} from a great distance)

The shell velocities (v_{shell}) (i.e. the velocity measured at a specific radius) for each plunger are-

Drip

\left(1-\frac{2M}{r_o}\right)^{-1/2}\left(\frac{2M}{r}-\frac{2M}{r_o}\right)^{1/2}

Rain

\left(\frac{2M}{r}\right)^{1/2}

Hail

\left[\frac{2M}{r}+v_{far}^2\left(1-\frac{2M}{r}\right)\right]^{1/2}

where M=Gm/c^2 (multiply by c for SI units). If you use the above equations, you'll see that regardless of whether an object is dropped from rest close to the event horizon or whether it approaches from a great distance at close to c, all objects cross the event horizon, relative to the EH, at c. These equations only apply to radii greater than 2M as there are no stable shells (or stable r) inside the event horizon.

For the velocity of an in-falling object as observed from infinity, multiply the above equations by (1-2M/r).
 
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Thanks for your helpful answers.
 
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