Topology: Clopen basis of a space

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SUMMARY

The collection of clopen sets in the space {0,1}^{\mathbb{N}} forms a countable basis under the product topology derived from the discrete topology on {0, 1}. The basic open sets in this topology are defined as products of open sets from each factor, where only finitely many factors differ from the entire space. The proof hinges on the countability of finite subsets of the natural numbers, which confirms the assertion made in the homework statement.

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  • Understanding of discrete topology
  • Familiarity with product topology
  • Knowledge of clopen sets
  • Basic combinatorial principles regarding finite subsets
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  • Study the properties of discrete topology in depth
  • Explore the concept of product topology and its applications
  • Investigate the characteristics of clopen sets in topological spaces
  • Review combinatorial mathematics related to finite sets
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Mathematics students, particularly those studying topology, as well as educators and researchers interested in foundational concepts of topological spaces.

talolard
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Homework Statement



So, I'm going through a proof and it is shamelessly asserted that the collection of clopen sets of {0,1}^{\mathbb{N}} is a countable basis. Can anyone reasure me of this, point me in the direction of proving it.
Thanks
Tal
 
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I assume you mean that \{0, 1\} is to be given the discrete topology and then \{0, 1\}^\mathbb{N} gets the product topology based on that.

Remember that the basic open sets of the product topology on a product \textstyle\prod_\lambda X_\lambda are the the sets \textstyle\prod_\lambda U_\lambda where each U_\lambda is open in X_\lambda and only finitely many of the U_\lambda differ from X_\lambda.

How many finite subsets does \mathbb{N} have?
 
Got it.
Thanks.
 

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