Torque exerted on trap door by rope

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To calculate the torque exerted on a trap door by a rope, the problem involves a trap door measuring 1.55 m on each side, held at a 65.0° angle and attached to a wall by a rope pulling perpendicularly. The mass of the trap door is 14.6 kg, and the torque is determined using the formula Torque = F(r), where F represents the force and r the distance from the pivot. The solution requires analyzing the moments around the pivot point, considering both the torque from the rope and the weight of the door, which must be resolved into components. Understanding the center of mass is crucial for accurately calculating the torque. The discussion emphasizes the importance of balancing moments in statics problems.
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Homework Statement


A trap door, of length and width 1.55 m, is held open at an angle of 65.0° with respect to the floor. A rope is attached to the raised edge of the door and fastened to the wall behind the door in such a position that the rope pulls perpendicularly to the trap door. If the mass of the trap door is 14.6 kg, what is the torque exerted on the trap door by the rope?



Homework Equations


Torque=F(r)


The Attempt at a Solution



Honestly I have no clue.
 
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This is a statics problem, so the sum of the moments/torques must equal zero. Find each of the moments about the pivot. One of the moments (torques) is due to the rope which is acting perpendicular to the plane (and moment arm) of the trapdoor. The other is the weight, which must be resolved into normal and parallel components with respect to the plane of the trapdoor.

Think about center of mass.
 

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