Torque on a spherical planetoid galaxy

AI Thread Summary
The discussion centers on calculating the rate of change of angular momentum and the external torque acting on a spherical planetoid with a given spin angular momentum. The user proposes that the rate of change can be expressed as Lsin(23.5)w, where L is the angular momentum and w is the angular velocity derived from the time taken for the angular momentum vector to complete a cone. They also suggest that torque can be calculated using the formula rFsin(23.5), with r being the radius of Earth. However, there is confusion regarding the application of these formulas, particularly in the context of the planetoid's specific parameters. The discussion highlights the need for clarity in the relationship between angular momentum, torque, and the geometry of the motion.
Borat321
Messages
5
Reaction score
0
Hi - I had a question on webassign - here is the question.

A spherical planetoid in a galaxy far, far away has spin angular momentum of magnitude L = 5.9e+35 kg m2/s directed out of its north pole. An external torque acts on it, such that the planetoid's axis of rotation, and hence its angular momentum vector, gradually changes direction, describing a cone with half-angle 23.5 degrees as shown in the figure.
Define the y-axis as straight up in the figure (the vertical arrow shown). Define the x-axis as to the right.

Suppose the angular momentum vector takes 21200 years to swing once around the cone shown. What is the magnitude of the rate of change of the planetoid's angular momentum in that direction at the instant shown? (Hint: consider the analogy between how the component of angular momentum changes with time, and how the position of a particle in circular motion changes with time.

What is the magnitude of the external torque exerted on the planetoid?

I thoiught that the rate of cahnge of the planetoid's angular momentum can just be Lsin(23.5)w, where L=5.9e+35 and w = 2pi/21200 converted into seconds.

Also, I thought torque would just be rFsin23.5, where r = radius of Earth, but where am I going wrong?
 
Physics news on Phys.org
The rate of change of the planetoid's angular momentum in that direction would be: Lsin(23.5)w, where L is the magnitude of the spin angular momentum (5.9e+35 kg m2/s) and w is the angular velocity (2π/21200). The magnitude of the external torque exerted on the planetoid is: T = Lsin(23.5)w, where L is the magnitude of the spin angular momentum (5.9e+35 kg m2/s) and w is the angular velocity (2π/21200).
 
I multiplied the values first without the error limit. Got 19.38. rounded it off to 2 significant figures since the given data has 2 significant figures. So = 19. For error I used the above formula. It comes out about 1.48. Now my question is. Should I write the answer as 19±1.5 (rounding 1.48 to 2 significant figures) OR should I write it as 19±1. So in short, should the error have same number of significant figures as the mean value or should it have the same number of decimal places as...
Thread 'A cylinder connected to a hanging mass'
Let's declare that for the cylinder, mass = M = 10 kg Radius = R = 4 m For the wall and the floor, Friction coeff = ##\mu## = 0.5 For the hanging mass, mass = m = 11 kg First, we divide the force according to their respective plane (x and y thing, correct me if I'm wrong) and according to which, cylinder or the hanging mass, they're working on. Force on the hanging mass $$mg - T = ma$$ Force(Cylinder) on y $$N_f + f_w - Mg = 0$$ Force(Cylinder) on x $$T + f_f - N_w = Ma$$ There's also...
Back
Top