Torus - Singh, Example 2.2.5 - Baffled by certain aspects

  • Thread starter Thread starter Math Amateur
  • Start date Start date
  • Tags Tags
    Example Torus
Math Amateur
Gold Member
MHB
Messages
3,920
Reaction score
48
I am baffled by some aspects of the torus ... I hope someone can help ...

I am puzzled by some aspects of Singh's treatment of the torus in Example 2.2.5 ( Tej Bahadur Singh: Elements of Topology, CRC Press, 2013) ... ...

Singh's Example 2.2.5 reads as follows:

?temp_hash=1d6597f8eee43d0cd15ffc346eef67d4.png


My questions related to the above example of Singh's are as follows:Question 1

C_1 as defined above seems to me to be a circle at 'height' z = 1, around the z-axis ... why (for what reason?) did Singh choose C_1 to be at 'height' z = 1?

Why not choose C_1 as \{ (x,y, 0) \ | \ x^2 + y^2 = 4 \}?

Such a choice seems more natural if you are rotating C_2 around the z-axis, since C_1 is at level z = 0 ... ...Question 2

h \ : \ T \rightarrow C_1 \times C_2

maps (x,y,z) onto two three dimensional points in Euclidean 3-space and so essentially maps (x,y,z) into Euclidean 6-space ... ..

... BUT ...

T is homeomorphic to S^1 \times S^1 which is embedded in Euclidean 4-space ... ... how can this be ...


I hope someone can clarify the above issues/questions ...

Peter
 

Attachments

  • Singh - Example 2.2.5.png
    Singh - Example 2.2.5.png
    43.2 KB · Views: 730
Last edited:
Physics news on Phys.org
Question 2: C1 and C2 are both circles in R^3 so the product is embedded in R^6.

Question 1. The top of the torus,T, is a circle at height of 1 above the xy-plane. and has radius 2
The circle C2 is the same circle.
 
Last edited:
Math Amateur said:
I am baffled by some aspects of the torus ... I hope someone can help ...

I am puzzled by some aspects of Singh's treatment of the torus in Example 2.2.5 ( Tej Bahadur Singh: Elements of Topology, CRC Press, 2013) ... ...

Singh's Example 2.2.5 reads as follows:

?temp_hash=1d6597f8eee43d0cd15ffc346eef67d4.png


My questions related to the above example of Singh's are as follows:Question 1

C_1 as defined above seems to me to be a circle at 'height' z = 1, around the z-axis ... why (for what reason?) did Singh choose C_1 to be at 'height' z = 1?

Why not choose C_1 as \{ (x,y, 0) \ | \ x^2 + y^2 = 4 \}?

Such a choice seems more natural if you are rotating C_2 around the z-axis, since C_1 is at level z = 0 ... ...Question 2

h \ : \ T \rightarrow C_1 \times C_2

maps (x,y,z) onto two three dimensional points in Euclidean 3-space and so essentially maps (x,y,z) into Euclidean 6-space ... ..

... BUT ...

T is homeomorphic to S^1 \times S^1 which is embedded in Euclidean 4-space ... ... how can this be ...


I hope someone can clarify the above issues/questions ...

Peter
lavinia said:
Question 2: C1 and C2 are both circles in R^3 so the product is embedded in R^6.

Question 1. The top of the torus,T, is a circle at height of 1 above the xy-plane. and has radius 2
The circle C2 is the same circle.
Thanks so much for your help Lavinia ... ...

... ... BUT ... for Question 1 ... do you mean "The circle C1 is the same circle"and ... if it is supposed to be C_1, then could Singh have alternatively, defined C_1 as

C_1 as \{ (x,y, -1) \ | \ x^2 + y^2 = 4 \} ...

as this seems to define the bottom of the torus ...

Hope you can help further ... ...

Peter
 
Math Amateur said:
Thanks so much for your help Lavinia ... ...

... ... BUT ... for Question 1 ... do you mean "The circle C1 is the same circle"and ... if it is supposed to be C_1, then could Singh have alternatively, defined C_1 as

C_1 as \{ (x,y, -1) \ | \ x^2 + y^2 = 4 \} ...

as this seems to define the bottom of the torus ...

Hope you can help further ... ...

Peter
yes he could have defined C_1 as the bottom of the torus.
 
Thanks Lavinia ... Appreciate the help ...

Just quickly ... In your answer to question 1, did you mean: The Circle C1 is the same circle?

Peter
 
Math Amateur said:
Thanks Lavinia ... Appreciate the help ...

Just quickly ... In your answer to question 1, did you mean: The Circle C1 is the same circle?

Peter
yes. sorry
 
Thanks again Lavinia ... most helpful ...

Peter
 
Back
Top