- #1
smashbrohamme
- 97
- 1
Ok you have a disk that is originally rotating at a Wo=6rad/s. The Angular acceleration=4rad/s². Determine the magnitude of the total acceleration (combinaton of An and At) at point A just after 2 revolutions.
The Circle is a 2ft Diameter circle with point A being 1.5ft distance from the center.
Ok first in order to use the total acceleration equations which is An=W²r and At=*angularacceleration*r
you have to find the final angular velocity of this disk.
so you would use the equation W²=Wo²+2(4)(2pie*2) I converted to revolutions using 2pie.
that would give me a W=11.68.
Now that I have a W of the whole wheel, I can simple use the An,At formulas to find the true acceleration at POINT A.
An=(11.68)²*1.5= 204.6 r=1.5 is simply the distance from the center of POINT A right?
At=(4)(1.5)=6 same deal, R is simply 1.5 since it is the distance from the center, or distance of contact with POINT A.
Now you just simply do 204.6²+6²= and square root the answer...
I am making sure I am doing this correctly. Please verify if this is the correct way.
The Circle is a 2ft Diameter circle with point A being 1.5ft distance from the center.
Ok first in order to use the total acceleration equations which is An=W²r and At=*angularacceleration*r
you have to find the final angular velocity of this disk.
so you would use the equation W²=Wo²+2(4)(2pie*2) I converted to revolutions using 2pie.
that would give me a W=11.68.
Now that I have a W of the whole wheel, I can simple use the An,At formulas to find the true acceleration at POINT A.
An=(11.68)²*1.5= 204.6 r=1.5 is simply the distance from the center of POINT A right?
At=(4)(1.5)=6 same deal, R is simply 1.5 since it is the distance from the center, or distance of contact with POINT A.
Now you just simply do 204.6²+6²= and square root the answer...
I am making sure I am doing this correctly. Please verify if this is the correct way.