Total displacement using vector diagram

AI Thread Summary
The discussion focuses on calculating the total displacement of a car that travels 50 miles east, 30 miles north, and then 25 miles at a 30-degree angle east of north. The relevant equations for determining the total displacement include summing the x and y components of each leg of the journey. The user shares their vector diagram and calculations, seeking validation of their approach. Feedback emphasizes the importance of clear image presentation and adherence to homework guidelines. The overall goal is to accurately determine the car's total displacement from its starting point.
Muhammad Khalid Khan
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A car is driven eastward for a distance of 50 miles, then northward for 30 miles, and then in a direction 30 degree east of north for 25 miles. Draw the vector diagram and determine the total displacement of the car from its starting point.


The relevant equations I used here are: i) rx= ax + bx + cx
ii) ry=ay + by + cy
iii) r= √(rx2 + ry2)
My attempt regarding this problem is as follows: (Please see the photos)
 
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Muhammad Khalid Khan said:
View attachment 110471 View attachment 110472 A car is driven eastward for a distance of 50 miles, then northward for 30 miles, and then in a direction 30 degree east of north for 25 miles. Draw the vector diagram and determine the total displacement of the car from its starting point.

The relevant equations I used here are: i) rx= ax + bx + cx
ii) ry=ay + by + cy
iii) r= √(rx2 + ry2)
My attempt regarding this problem is as follows: (Please see the photos)
Looks correct to me.
 
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Buffu said:
Looks correct to me.
Have I done it right?
 
In the future, please take care to post images that aren't rotated. Also, please don't delete the three parts of the homework template.
 
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I picked up this problem from the Schaum's series book titled "College Mathematics" by Ayres/Schmidt. It is a solved problem in the book. But what surprised me was that the solution to this problem was given in one line without any explanation. I could, therefore, not understand how the given one-line solution was reached. The one-line solution in the book says: The equation is ##x \cos{\omega} +y \sin{\omega} - 5 = 0##, ##\omega## being the parameter. From my side, the only thing I could...
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