Total energy stored in the electric fields, exess energy

AI Thread Summary
When one charged capacitor with 4.0 J of stored energy is connected in parallel to an uncharged capacitor, the total energy stored in the system becomes 2 J after charge redistribution. This reduction in energy occurs because some energy is lost as heat during the redistribution process. The excess energy is not stored but dissipated, illustrating the conservation of energy principle. The final energy in the system reflects the equal distribution of charge between the two capacitors. Understanding these energy transformations is crucial in analyzing capacitor circuits.
Vaidotas151
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Homework Statement



one capacitor is charged until its stored energy is 4.0 J, the charging battery then being removed. a second uncharged capacitor is then connected to it in parallel. if the charge distributes equally what is now the total energy stored in the electric fields? where the exess energy go? Answer must be 2 J

Homework Equations





The Attempt at a Solution

 
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Vaidotas151 said:

Homework Statement



one capacitor is charged until its stored energy is 4.0 J, the charging battery then being removed. a second uncharged capacitor is then connected to it in parallel. if the charge distributes equally what is now the total energy stored in the electric fields? where the exess energy go? Answer must be 2 J

Homework Equations





The Attempt at a Solution

Hi Vaidotas151, http://img96.imageshack.us/img96/5725/red5e5etimes5e5e45e5e25.gif

You are required to show an attempt at this, by filling in parts 2 & 3 of the template.
 
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