Transfer Function Help: Find Soln for Attached Image

[triden]

Homework Statement

I need help finding the transfer function for the attached image.

Homework Equations

The Attempt at a Solution

I combined the 1/6F cap and the 1 ohm resistor into a single impedence. I know the AV of the opamp is -0.5/(6s+1). After that I am stumped.

Is there a name of this specific circuit?

 

[gneill]

Have you tried nodal analysis? Call node "a" the junction of the input 1Ω resistor and the capacitors, call node "b" the inverting input of the op-amp. The output of the op-amp can be Vo, while the circuit input signal is Vi. Remember the properties of an op-amp; there's a negative feedback loop, so what can you say about the voltage at the input terminals? How about the current?

 

[triden]

Ok, I know I am on the right track. I have tried a couple things, but didn';t quite get it. I guess my problem is relating V- to V+. I want to think that V- = V+ = 0, but I don't think that's right. I know the answer (it is at the top of the sheet). Here is what I have so far now.

 

[triden]

I got it :) Thx anyhow! Little bit of patience and practice pays off

 

[DeeNos]

Hello,

Thank you for reaching out for assistance with finding the transfer function for this circuit. It appears to be a non-inverting amplifier circuit with a capacitor in the feedback loop.

To find the transfer function, we can use the standard equation for a non-inverting amplifier:

Vout/Vin = 1 + (R2/R1)

In this case, R2 is the impedance of the 1 ohm resistor and the 1/6F capacitor in parallel, which can be simplified to 6s/7. R1 is the input impedance of the opamp, which is typically very high and can be assumed to be infinity for most circuits. Therefore, the transfer function for this circuit can be written as:

Vout/Vin = 1 + (6s/7)

I hope this helps! Please let me know if you have any further questions.