Transistor at cutoff, conductance, or saturation?

AI Thread Summary
When the VBB potentials are flipped, the transistor will be in cutoff because no current flows to the base, resulting in no current through the transistor. This condition effectively disconnects the transistor from the circuit. The terminology used is important, as the correct term for the input terminal of a bipolar junction transistor is "base," not "gate." Understanding these concepts is crucial for electronics tests. Clarity on these points can aid in mastering transistor behavior.
Femme_physics
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Hi everyone, took a bit of a break lately...but with 6 days left to the final test of electronics, I figured I'd clear up some understandings I have

Homework Statement



http://img225.imageshack.us/img225/4474/vbbreversed.jpg

I'm asked if the VBB potentials are flipped, at what condition will the transistor be? (conductance, saturation, cutoff...)

The Attempt at a Solution



I say cutoff, because no current flows to the gate of the transistor hence no current flows in the transistor. The transistor acts like a disconnection in the circuit.
 
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Good! :)

(Although you should call it the "base" instead of the "gate" for this type of transistor.)
 
Thanks ILS :)
 
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