Transition A produces light with a wavelength of 400 nm

AI Thread Summary
The discussion centers on understanding the relationship between energy and wavelength in photon transitions. Transition A emits light at a wavelength of 400 nm, while Transition B has twice the energy of A. The key equation relating energy (E) and wavelength (λ) is E = hc/λ, where h is Planck's constant and c is the speed of light. Doubling the energy indeed results in halving the wavelength, leading to a wavelength of 200 nm for Transition B. The participant expresses a desire to learn and grasp the concepts involved in these calculations.
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I am having difficulty with this problem. I have solved all of the other ones and got them correct, but this one is stumpimg me.

Transition A produces light with a wavelength of 400 nm. Transition B involves twice as much energy as A. What wavelenth light does it produce?

Help please.
 
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I am not looking for the answer from anyone. I just need to know how to figure it out. I want to learn and need some assistance.
 


What is the equation relating energy and wavelength of a photon and how would changing the energy change the wavelength?

Answer in the spoiler. 1st Spoiler just has the equation, 2nd has a solution.
Eλ=hc
So for λ=400 nm E=Eo
2Eoλ=hc

So to get the same value for hc, λ must be half of the original value, so:
λ=200 nm.
 


Thanks so much for the help. I am having learning this, but it has been 20years since I have taken college algebra and there is much more going on here than algebra. Love the knowledge!
 


I'm assuming that when you double the frequency you double the energy? Which would equal halving the wavelength?
 


Ah I am late,your query has been answered already.
-ibysaiyan
 
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