Transverse Waves- Verticle Rope

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SUMMARY

The discussion focuses on the analysis of transverse waves in a vertical rope, specifically a 3-meter long rope. The propagation speed of transverse waves is determined to be independent of the rope's mass and overall length, calculated using the formula sqrt(tension/mu). For the maximum propagation speed to equal the speed of sound in air (330 m/s), the required length of the rope is approximately 11,000 meters. The user encountered difficulties in calculating the round-trip time for a wave traveling from the bottom to the top of the rope and back, due to a lack of information on wavelength, amplitude, or frequency.

PREREQUISITES
  • Understanding of wave mechanics and propagation speed
  • Familiarity with tension and mass per unit length (mu) in ropes
  • Basic knowledge of gravitational force and its impact on tension
  • Ability to apply mathematical formulas related to wave speed
NEXT STEPS
  • Learn about wave propagation in different media, focusing on transverse waves
  • Study the relationship between tension, mass per unit length, and wave speed in ropes
  • Explore the calculation of wave travel time in various configurations
  • Investigate the effects of amplitude and frequency on wave behavior
USEFUL FOR

Students studying physics, particularly those focusing on wave mechanics, as well as educators and anyone interested in the dynamics of transverse waves in ropes.

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Homework Statement


A heavy rope 3 m long is attached to the ceiling and allowed to hang freely. Let y = 0 denote the bottom end of the rope. To get started on this problem, imagine cutting the rope at an arbitrary value of y. Draw a free body diagram of each of the two pieces of rope to determine the tension at the point where the rope was cut.

3.1 Determine the propagation speed of transverse waves on the rope and show that this speed is independent of the rope's mass and overall length.


3.2 How long would the rope have to be in order for the maximum propagation speed to be equal to the speed of sound in air (which we will take to be 330 m/s)?


3.3 Calculate the time it takes for a transverse wave to travel from the bottom of the 3 m long rope to the top and then back to the bottom.


3.4 Compare this round-trip time to that for a horizontal rope with the same tension as the average tension of the vertical rope.



2. Homework Equations and

The Attempt at a Solution



All right, here's what I tried:

3.1 If you cut the rope at an arbitrary point y, you can get the tension by the gravitational force on that section of the rope, which would be y*g*mu, with mu being the mass per unit length of the rope. Since propagation speed is sqr(tension/mu), it cancels out to sqrt(y*g), not being dependent on the mass or the total length of the rope.

3.2 This one was easy, I just set 330 m/s to sqrt(y*g), and found y to be 1.1x10^4 m.

3.3 This is where I get stuck. All of the wave equations I know don't let me simplify this enough to be able to solve for T. I don't know the wavelength,amplitude or frequency, so how can I solve for the period?

I really appreciate any help! Thanks in advance :o).
 
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