Suppose that the 0[tex]\int[/tex]1 g(t)dt=5.
Compute the value of 1[tex]\int[/tex]e g(ln(t))/t dt
The Attempt at a Solution
I think that u substitution is the best way to solve.
If you set u=ln(t), then du=1/t dt which is in your integration. I do not know how to incorporate the given value of the integral of g(t) into the second integration, especially because the bounds of integration are different.
Thank you for any help!