Trig Identity Problem: Solve sin \theta = -5/13 & cos \theta = -(√194)/13

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The discussion addresses the trigonometric identity problem involving sin θ = -5/13 and cos θ = -√194/13, with the angle θ constrained between (3π/2) and 2π. Participants clarify that the correct cosine value should be cos θ = -12/13, noting that the cosine is negative in the fourth quadrant. There is confusion over the application of the Pythagorean identity sin²θ + cos²θ = 1, with emphasis on correctly squaring the sine value. The importance of remembering the signs of trigonometric ratios in different quadrants is highlighted, particularly that cosine is positive in the first quadrant and negative in the fourth. Overall, the conversation reinforces the need for accuracy in trigonometric calculations and quadrant sign rules.
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Sin \theta = -5/13,
(3\pi / 2) < \theta < 2 \pi

So I got cos \theta = - (sqrt 194) / 13
Is this the right answer?
 
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How u manage to get that? Its incorrect
 
I used sin^2theta + cos^2theta = 1
 
And I bet that when you did, you squared -5/13 and got -25/169? If so, that's not right -- it's +25/169.

Also, what quadrant is
\frac{3\pi}{2} &lt; \theta &lt; 2\pi
? And what is the sign for the cosine ratio in that quadrant?

Finally, please don't use LaTex for single characters. It doesn't look right. Click the inequality I wrote above to see how to type it.
 
Cos theta = -12/13 . And (-) since it's in quadrant IV.
 
Thanks
 
CrossFit415 said:
Cos theta = -12/13 . And (-) since it's in quadrant IV.

No, no, no, cosine is positive in Q IV. You really need to remember the signs of the trig ratios in each quadrant.

Q I: All
Q II: sine (and cosecant)
Q III: tangent (and cotangent)
Q IV: cosine (and secant)

When I learned this, I was taught the mnemonic "All Students Take Calculus" to help me remember.
 
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