Trig idents while computing limit

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The discussion revolves around the difficulty in solving a limit problem using trigonometric identities. The user attempted to apply the identities for cosine and sine to expand the terms but struggled with factoring due to the presence of the sin(h) term. Another participant suggests factoring sin(x) from the first two terms and cos(x) from the next two terms to align with the solution guide. There is also confusion regarding the denominator in the user's work. The conversation highlights the importance of careful expansion and factoring in trigonometric limit problems.
quicksilver123
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My screenshots show an attempt at a solution and the given solution path from the book, but I can't seem to figure it out.
 

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That is the identity I used to expand the (x+h) terms but could not factor to the next step due to the sin(h) term... unless I made an error in my expansion that I haven't caught?
 
In your work, factor a sin(x) from the first 2 terms and cos(x) from the next 2 terms. You should now have the same as the solution guide. Note that it takes 2 lines to display theirs. I don't know what you've done in the denominator, though. .
 
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Thanks. I don't know why I didn't see that.
 
First, I tried to show that ##f_n## converges uniformly on ##[0,2\pi]##, which is true since ##f_n \rightarrow 0## for ##n \rightarrow \infty## and ##\sigma_n=\mathrm{sup}\left| \frac{\sin\left(\frac{n^2}{n+\frac 15}x\right)}{n^{x^2-3x+3}} \right| \leq \frac{1}{|n^{x^2-3x+3}|} \leq \frac{1}{n^{\frac 34}}\rightarrow 0##. I can't use neither Leibnitz's test nor Abel's test. For Dirichlet's test I would need to show, that ##\sin\left(\frac{n^2}{n+\frac 15}x \right)## has partialy bounded sums...