Trig substitution should be simple but it's driving me nuts

pugtm
Messages
17
Reaction score
0

Homework Statement


[itex]\int x/sqrt{(x^{2}+4)}[/itex]


Homework Equations


x=2tanx


The Attempt at a Solution


x=2tanx
[itex]\int[/itex]2tan[itex]\vartheta[/itex]/[itex]\sqrt{tan^2\vartheta}[/itex]+4
2/2 *[itex]\int[/itex]tan/sec

[itex]\int[/itex]sin=-cos

now is the part where i am stuck
i know from using substitution that the answr should be [itex]\sqrt{x^2+4}[/itex]
but no matter how i manipulate it, it comes out strange.
all help is appreciated
 
on Phys.org
The integral you're trying to evaluate is
[tex]\int\frac{x}{\sqrt{x^2+4}}\,dx[/tex]
Note the presence of the dx. That's what you forgot to account for when you did the trig substitution.
 
how do you get rid of the natural log at the end?
 
What natural log? You apparently made another mistake.
 
the new integral is
int 2tan(x)sec(x)^2/Sqrt(4tan(x)^2+4)
the sec^2 cancel out making it the integral of 2tan(x)=-2lncos(x)
 
Slow down and look at it more carefully.
[tex]\int \frac{2 \tan \theta \ \sec^2\theta}{\sqrt{4\tan^2\theta+4}}\,d\theta = \int \frac{2 \tan \theta \ \sec^2\theta}{2\sqrt{\sec^2\theta}}\,d\theta[/tex]
 
pugtm said:
i know from using substitution that the answr should be [itex]\sqrt{x^2+4}[/itex]
but no matter how i manipulate it, it comes out strange.
all help is appreciated

I'm not sure that's what you mean, but I hope you noticed that there's a much simpler substitution possible :-)

Anyway, the others are correct about your mistakes :-)
 
thank you all for your timely assistance
 

Similar threads

  • · Replies 22 ·
Replies
22
Views
4K
  • · Replies 3 ·
Replies
3
Views
2K
  • · Replies 6 ·
Replies
6
Views
2K
  • · Replies 8 ·
Replies
8
Views
3K
  • · Replies 6 ·
Replies
6
Views
4K
  • · Replies 4 ·
Replies
4
Views
2K
  • · Replies 5 ·
Replies
5
Views
18K
  • · Replies 10 ·
Replies
10
Views
3K
  • · Replies 4 ·
Replies
4
Views
2K
  • · Replies 4 ·
Replies
4
Views
2K