Trigonometric substitution for integral with exponential and square root

annoymage
Messages
360
Reaction score
0

Homework Statement



Evaluate \int\frac{e^t}{\sqrt{e^2^t+9}}

Homework Equations



N/A

The Attempt at a Solution



i'm using substitution

tan \theta = \frac{e^t}{3}

or i also can use

tan \theta = \frac{3}{e^t}

both will get the same answer.

am i right? because my lecturer told i was wrong, I'm really sure that i did right..
can anyone help me if I am wrong please
 
Physics news on Phys.org
Hi annoymage! :smile:

(never leave out the "dt" after an ∫ :wink:)

Both look ok to me.
 
It is a possible substitution, but I can't tell you what's wrong until you show your work. That said using a hyperbolic substitution is a lot easier than the one you did.
 
tiny-tim said:
Hi annoymage! :smile:

(never leave out the "dt" after an ∫ :wink:)

Both look ok to me.


owho, i forgot the "dt" ;P,

Cyosis said:
It is a possible substitution, but I can't tell you what's wrong until you show your work. That said using a hyperbolic substitution is a lot easier than the one you did.

i guess this what my lecturer wanted me to do (hyperbolic),

k thanks tiny-tim and cyosis, i fell a lot better now, ahahaa
 
There are two things I don't understand about this problem. First, when finding the nth root of a number, there should in theory be n solutions. However, the formula produces n+1 roots. Here is how. The first root is simply ##\left(r\right)^{\left(\frac{1}{n}\right)}##. Then you multiply this first root by n additional expressions given by the formula, as you go through k=0,1,...n-1. So you end up with n+1 roots, which cannot be correct. Let me illustrate what I mean. For this...
Back
Top