Trigonometrical Identities and Simple Equations

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Hi there, I am struggling with trigonometrical identities and how to use them effectively. I can work out simpler problems but I can't seem to get my head round slightly bigger ones like this:-

Simplify:-

sin^4(x) + 2sin^2(x)cos^2(x) + cos^4(x)

I 've tried substituting "2sin^2(x)cos^2(x)" with

sin^2(x) = 1 - cos^2(x)

and also tried

cos^2(x) = 1 - sin^2(x)

but end up going round in circles. Can somebody give me some pointers please!

Thanks!
 
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sin x = s, cos x = c

Hint : s^4 + 2s^2c^2 + c^4 = (s^2)(s^2) + (s^2)(c^2) + (c^2)(s^2) + (c^2)(c^2).

Collect the terms and see what you come up with.
 
Sin^2x + cos^2x =1
 
As Curious has hinted this has been cleverly constructed to be a quadratic in trigonometric functions. It should be quite easy to solve now.
 
Thanks for that! Must remember to factor! That made it easier to solve.
 
Prove $$\int\limits_0^{\sqrt2/4}\frac{1}{\sqrt{x-x^2}}\arcsin\sqrt{\frac{(x-1)\left(x-1+x\sqrt{9-16x}\right)}{1-2x}} \, \mathrm dx = \frac{\pi^2}{8}.$$ Let $$I = \int\limits_0^{\sqrt 2 / 4}\frac{1}{\sqrt{x-x^2}}\arcsin\sqrt{\frac{(x-1)\left(x-1+x\sqrt{9-16x}\right)}{1-2x}} \, \mathrm dx. \tag{1}$$ The representation integral of ##\arcsin## is $$\arcsin u = \int\limits_{0}^{1} \frac{\mathrm dt}{\sqrt{1-t^2}}, \qquad 0 \leqslant u \leqslant 1.$$ Plugging identity above into ##(1)## with ##u...
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