Trigonometry Question: Find the Value of sin(α +2β) When cot (α + β) = 0

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Homework Statement


If cot (α + β) = 0 then sin(α +2β) is
the options are
a. sin α b. cos α c. sin β d. cos 2β


Homework Equations


There is as such no equation


The Attempt at a Solution


I did try to solve it but I kept arriving at the wrong answer. The correct answer is c. sin β while the answer I keep getting is a. sin α
 
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Maybe you can show us what you have so far, and we can try to find the error.
 
Are you sure that c) is the correct answer? Try with α=60° and β=30°. I think your result is the correct one.

ehild
 
mia5 said:

Homework Statement


If cot (α + β) = 0 then sin(α +2β) is
the options are
a. sin α b. cos α c. sin β d. cos 2β


Homework Equations


There is as such no equation


The Attempt at a Solution


I did try to solve it but I kept arriving at the wrong answer. The correct answer is c. sin β while the answer I keep getting is a. sin α

Your answer (sin α) is correct.
 
There are two things I don't understand about this problem. First, when finding the nth root of a number, there should in theory be n solutions. However, the formula produces n+1 roots. Here is how. The first root is simply ##\left(r\right)^{\left(\frac{1}{n}\right)}##. Then you multiply this first root by n additional expressions given by the formula, as you go through k=0,1,...n-1. So you end up with n+1 roots, which cannot be correct. Let me illustrate what I mean. For this...
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