Triple Integral Help: Find Mass in Cylindrical Coords

bdario1
Messages
1
Reaction score
0
Find the mass of the region (in cylindrical coordinates)r^3<=z<=1 , where the density function is r(r;q; z) = 9z.

This is what I got so far

0 <= r<= 1; 0 <= q <= 2p:
hence need to compute the integral
Z from 0 to 2pi Z from 0 to 1 Z r^3 to 1 9zdzrdrdq:
We thus obtain
9p Z 0 to 1(1^2-r^6) r dr


Now this is where I am not able to get to the answer not sure why.
 
Physics news on Phys.org
welcome to pf!

hi bdario1! welcome to pf! :smile:

(hav an integral: ∫ and a theta: θ and a pi: π and try using the X2 icon just above the Reply box :wink:)
bdario1 said:
Find the mass of the region (in cylindrical coordinates)r^3<=z<=1 , where the density function is r(r;q; z) = 9z.

This is what I got so far

0 <= r<= 1; 0 <= q <= 2p:
hence need to compute the integral
Z from 0 to 2pi Z from 0 to 1 Z r^3 to 1 9zdzrdrdq:
We thus obtain
9p Z 0 to 1(1^2-r^6) r dr


Now this is where I am not able to get to the answer not sure why.

looks ok to me (though not very readable) :confused:

what is the answer?​
 
I think you should obtain Pi/4 9^3 as answer. Please be more careful when formulating your problem, because it not very readable indeed.
 
Back
Top