Trouble calculating the acceleration

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SUMMARY

The discussion centers on calculating acceleration when the initial velocity is unknown. The scenario involves a vehicle passing distance markers at specific time intervals, with the first marker (0.1 miles) reached in 16 seconds and the second marker (0.2 miles) in an additional 8 seconds. The correct formula for acceleration in this context is derived from the equation d = v0*t + (1/2)*a*t^2, where v0 is the initial velocity and a is the acceleration. The user is advised to set up two equations based on the given time intervals to solve for both initial velocity and acceleration.

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ERAUin08
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Hey everyone I need some help with a problem. I am having trouble calculating the acceleration since I don't the the initial velocity.

Homework Statement


You are driving on the highway when you come across a speedometer test where the distances are maked on signs. When you pass the 0 mile marker, rather than holding your speed constant you press on the accelarator and hold it constant. You pass the 0.1 mile marker 16 s later, and the 0.2 mile marker 8 seconds after the 0.1 marker. a) What did you speedometer read at the 0.2 mile? b) what was your acceleration?


Homework Equations


d=v/t
d=0.2 miles=322m
time=24 s

The Attempt at a Solution


a) 322m=v/24s
V=13m/s
b) For the acceleration I am not sure.

Thank you for your help
 
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If it's accelerating you CAN'T use v=d/t (and you can't use d=v/t anywhere. It's wrong). You have to use d=v0*t+(1/2)*a*t^2 where v0 is the initial velocity and a is the acceleration. Now if you put in the two given time points, you have two equations in the two unknowns v0 and a. Solve for them.
 

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