Trouble with local extrema graph

coverticus
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Homework Statement


Sketch a graph of a function f that is continuous on [1,5] and has no local maximum and minimum, but 2 and 4 are critical numbers.


Homework Equations





The Attempt at a Solution


Knowing 2 and 4 are critical numbers, I formed the base function x^{}2-6x+8. Not sure how to go about sketching the graph the meets the stipulations beyond this.
 
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Just draw it. No need to actually have a concrete function.
 
Also, note that x^3 has no maximum or minimum but has a critical point where? What does that point look like?

Also, are you sure it's [1,5]?
 
So just sketch a graph that has no local extrema on [1,5]? If so how are 2 and 4 critical numbers?
 
Yes it is [1,5], and x^3 has a critical point at 0, and it has a slope of zero. Correct?
 
I still need somewhat of a solid answer here, do I just sketch a graph where x=0 on [1,5] or something different? Any help here would be great.
 
You sketch a graph where x=2 and x=4 have horizontal tangents, but aren't maxes or mins.
 
does that satisfy the continuity?
 
coverticus said:
does that satisfy the continuity?

Just draw the curve y=x^3 and look what happens at x=0. Now draw a curve with two points like that.
 
  • #10
how can you do that without creating an extrema?
 
  • #11
Put your pencil on a paper at x=1. Curve up until you reach x=2 then flatten out but don't go down. Increase out of the flat part till you get to x=4, then flatten out again. Then increase some more till you get to x=5.
 
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