Trouble with Trigonometric Integral? Get Help Now!

Physter
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Haven't done integrals in such a long time and now I'm having some trouble with this question here. Any help would be appreciated. Thanks :smile:

http://img331.imageshack.us/img331/4333/screen192cj.jpg
 
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Using the double angle formula as you do here is of course legitimate, however, there is a simpler choice:
Substitute u=\sin(t) instead.
 
This looks better I hope?

http://img312.imageshack.us/img312/5109/screen202ul.jpg
 
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+C of course :). But yes, that's correct.
 
^^^Arggg I always forget the constant. Thanks o:)
 

Thread 'Finding the nth roots of a complex number'

There are two things I don't understand about this problem. First, when finding the nth root of a number, there should in theory be n solutions. However, the formula produces n+1 roots. Here is how. The first root is simply ##\left(r\right)^{\left(\frac{1}{n}\right)}##. Then you multiply this first root by n additional expressions given by the formula, as you go through k=0,1,...n-1. So you end up with n+1 roots, which cannot be correct. Let me illustrate what I mean. For this...
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