Troubleshooting Bridge Rectifier in LT Spice Simulation

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The discussion focuses on troubleshooting a bridge rectifier in an LT Spice simulation for a linear power supply project. The user is struggling to achieve the expected sine wave output with negative values reflected on the positive x-axis after adding the bridge rectifier. Key advice includes plotting the voltage across the load resistor and ensuring the correct interpretation of the formula Vdc = 1.41 x Vac, which should use the RMS voltage and account for diode drops. The conversation emphasizes the importance of accurately calculating the input voltage to the regulator and suggests verifying the transformer secondary voltage in the simulation. Overall, the user is guided toward correcting their simulation approach for accurate results.
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Homework Statement


I am to build a linear power supply in four stages. However, at stage two, i have to add a bridge rectifier to the ouput of my transformer. My lecturer at university says i should get a graph that is a sine wave, with the negative values reflected into the positive x-axis (Volatage). I was wondering were am i going wrong?


2. The attempt at a solution
http://img399.imageshack.us/img399/1367/ltspice1gm7.jpg


Any help would be greatly appreciated.

Thanks.
 
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You need to plot the difference between rectifidp and rectifidn. Or, alternatively, plot the voltage across your load resistor, R5.
 
Yeah, had a suspicion it might have been that, but it took me a while to work out how to enter an expression. Only started using the program a few days ago, so I'm still getting used to it.

http://img218.imageshack.us/img218/138/ltspice2rc0.jpg

Many thanks for your help.
 
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I've got another problem. For a full wave bridge, with a capacitive filter, we are told the following relationship between Vdc [V(Regout)-V(Rectifidn)] and Vac [V(Secondary)]:

Vdc = 1.41 x Vac

However, I'm obtaining the following results:

http://img386.imageshack.us/img386/5310/lt4vr1.jpg

I'm just wondering if i have the wrong formula, or taking incorrect readings?

Thanks.
 
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lukesowersby said:
Vdc = 1.41 x Vac

A couple of things to keep in mind here:

That formula uses the rms voltage, not the amplitude, for Vac.

Also, it does not account for the 2 diode drops in the rectifier voltage.
 
Redbelly98 said:
A couple of things to keep in mind here:

That formula uses the rms voltage, not the amplitude, for Vac.

Also, it does not account for the 2 diode drops in the rectifier voltage.
Ah, forgot about rms. Thanks.

That equation was given a bridge rectifier (4 diodes) with a capacitor and load resistor, but exluding the regulator. So i assume to calculate Vac, if i want Vdc of 5, i simply calculate 5+the voltage acrross the regultor, all divided by 1.41.
 
You can check that on your Spice circuit, "transformer1 stage 5".

If you plot

V(rectifidp) - V(rectifidn)​
and
V(secondary)​

you can see if the regulator input voltage equals the amplitude of the transformer secondary.
 
Yeah, thanks for your help.
 
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