Trying to find how much work is done by friction

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To determine the work done by friction when dragging a table, one must consider the applied force and the angle of exertion. The problem states that the table moves at a constant velocity, implying that the net force is zero, and thus frictional force equals the horizontal component of the applied force. The equation for work done by friction can be derived using the work-energy principle, where work equals force times distance. The coefficient of friction is not needed if the forces are balanced, as the frictional force can be calculated directly from the applied force. Understanding the relationship between force, distance, and angle is crucial for solving this problem effectively.
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Homework Statement


A man drags a table 4.05 m across the floor, exerting a constant force of 51.0 N, directed 25.0° above the horizontal.

How much work is done by friction? Assume the table's velocity is constant.

Homework Equations


work= umgxsin\vartheta
f=uF

The Attempt at a Solution


I don't understand how I am supposed to find the coefficient of friction without knowing what the mass is.
 
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E=F*x
Energy=Force*distance

The Force and distance need to be parallel and that is where the 25'deg angle comes into play.

No need for mass, as people are fat enough.

Have fun!
 

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