Trying to find how much work is done by friction

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Homework Statement


A man drags a table 4.05 m across the floor, exerting a constant force of 51.0 N, directed 25.0° above the horizontal.

How much work is done by friction? Assume the table's velocity is constant.

Homework Equations


work= umgxsin[tex]\vartheta[/tex]
f=uF

The Attempt at a Solution


I don't understand how I am supposed to find the coefficient of friction without knowing what the mass is.
 
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E=F*x
Energy=Force*distance

The Force and distance need to be parallel and that is where the 25'deg angle comes into play.

No need for mass, as people are fat enough.

Have fun!