Two antenas (two waves wih the same frequency)

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The discussion revolves around calculating the phase difference and conditions for destructive interference between two antennas broadcasting at 95.0 MHz. The phase difference at observer P's location was determined to be 1.426 radians. The first instance of destructive interference occurs when the path length difference equals half the wavelength. The participants discussed using the equation for path length difference and the wavelength to find the distance from antenna A when destructive interference first occurs. The calculations involve determining the wavelength and applying it to the conditions for destructive interference along the x-axis.
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i really have some proplem with this question

Two antennas located at points A and B are broadcasting radio waves of frequency 95.0 MHz, perfectly in phase with each other. The two antennas are separated by a distance d= 9.30 m. An observer, P, is located on the x axis, a distance x= 60.0 m from antenna A, so that APB forms a right triangle with PB as hypotenuse. What is the phase difference between the waves arriving at P from antennas A and B?

1.426 rad
You are correct. Computer's answer now shown above.
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Now observer P walks along the x-axis toward antenna A. What is P's distance from A when he first observes fully destructive interference between the two waves?

If observer P continues walking until he reaches antenna A, at how many places along the x-axis (including the place you found in the previous problem) will he detect minima in the radio signal, due to destructive interference?

i calculated the phase difference between the two antenas but i didnt know how to to calculate the first time that i will receive a destructive interfernce i think that it is when the phase difference is pi*(2m+1)

this is how i calculted the first quesion first i calculated the distance BP which is 60.716m
then i used the equation (phase difference=2*pi*delta L/ג ) delta L=BP-AP and ג=c/frequency which is given
 
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You have already found ΔL. If at the point P instructive interference takes place, then
ΔL = (2n + 1)*λ/2. ...(1)
Find the wavelength.
Substitute the value of the wavelength in eq(1) and find n. If n is not an integer, at P there is no destructive interference. Select the nearest integer less than n. That is the first point of destructive interference with in 60 m.
 
hi
I tried to do what you told me but it does not help when i calculated n its negative and after i calculate n how can I calculate the distance AP I attached my try to solve the proplem
 

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ΔL = (2n + 1)*λ/2. ...(1)
Find the wavelength of the radio wave.
The first destructive interference will occur when ΔL = λ/2.
Now ΔL = sqrt(9.3^2 +x^2) - x...(2)
Put ΔL = λ/2 and solve for x.
Repeat the procedure for ΔL = 3λ/2, 5 λ/2...until x becomes negative.
 
Thanks a lot

I understand the proplem x is AP and I repeat the procedure to know how many time i have a destructive interfernce

if there is anything i can help with
 
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