(adsbygoogle = window.adsbygoogle || []).push({}); 1. The problem statement, all variables and given/known data

a)Two blocks are moving on a frictionless surface. The first block's mass is 1.07kg and its initial velocity is 5.98m/s. The second block's mass is 2.26kg and its initial velocity is 2.59m/s. What is the velocity of the 1.07kg block after the collision if the velocity of the second block is 5.15m/s after the collision?

b)If the initial velocity of the 2.26kg block is the same magnitude but in the opposite direction, what is the velocity of the 1.07kg block after the collision?

2. Relevant equations

m1v1=m2v2

3. The attempt at a solution

a)m1(vf+vi)=m2(vf+vi)

i made the velocities positive, because they travel n the same direction even after the collision.

(1.07kg)(vf+5.98m/s)=(2.26kg)(2.59m/s+5.15m/s)

vf= 10.37m/s

b) i will try after i get the first part right

this is wrong..im not sure what to do. please help.

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# Homework Help: Two block collision (momentum)

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