Two carts with masses of 8.0 kg and 1.8 kg, respectively, move on a friction

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Two carts with masses of 8.0 kg and 1.8 kg collide on a frictionless track, initially moving at velocities of 8.0 m/s and 3.5 m/s, respectively. The final speed after the collision is calculated using the conservation of momentum, taking into account the direction of motion. The correct formula incorporates the negative momentum of the cart moving in the opposite direction. The final speed is determined to be 5.89 m/s after resolving the initial momentum correctly. Understanding the direction of the carts is crucial for accurate calculations in collision problems.
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[SOLVED] Two carts with masses of 8.0 kg and 1.8 kg, respectively, move on a friction

Homework Statement



Two carts with masses of 8.0 kg and 1.8 kg, respectively, move on a frictionless track with velocities of 8.0 m/s and 3.5 m/s. The carts stick together after colliding head-on. Find the final speed.


Homework Equations



m1v1+m2v2 = v (m1 + m2)

v_final = (m1*v1 + m2*v2)/(m1+m2)

The Attempt at a Solution



(8*8)+(1.8*3.5)=70.3
so
70.3=(8+1.8)V
which is then 70.3=9.8V
V=7.17


but it says I'm doing it wrong. (webassign problem)
please show me how i did it wrong?? or what's wrong?
 
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You're adding the initial momenta, this is your problem. Define a coordinate system and determine which cart is moving in the positive direction, and which cart is moving in the negative direction (that is, which cart has a positive momentum, which cart has a negative momentum?).
 
Everything is perfect...except you forgot one little thing.

Since both Cars are going in opposite directions when they hit each other "head on" (one going left and one is going right), then one of them must be going in the "negative" direction. Let's define "left" as the positive direction:

m1v1-m2v2 = v (m1 + m2)

8(8) - 1.8(3.5) = Vfinal (8+1.8)
57.7=Vfinal (9.8)
Vfinal = 5.89 m/s
 
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